Restitution coefficient e has value 1 for elsatic collision.
In elastic collsion the total energy remains constant.
Restitution coefficient is the ratio of relative speed of separation after collsion to the relative speed of approach before collision.

Note the following notations:
J - angular momentum
K.E.- kinetic energy
I- moment of inertia (MoI)
omega represents angular speed.
1 & 2 are for two cases.(situations)

No impact as no "external" force.

what we need to solve the problem, is value of two masses and their respective acceleration.

What we need to solve the problem is the respective values of velocities alongwith value of mass.
As mass appeares in numerator and denominator so converting it into kg is not required.

All measurements has been done from center of original disc denoted by O.

What we need is net mass and speed of fragments with eqaul mass.

In example PV denoted by r1 and r2 is given for m1 and m2.

Some tips for preparation
1. When you start preparing for any exam, your first and foremost step should be to go through the syllabus of that exam along with the questions asked in the previous years of that exam and
A. Try to understand the trend
B. Try to understand the level of questions
C. Identify your strong and weak topics and plan how much importance to give to each topic accordingly
D. Work on the precise approach to solve questions so that maximum number of questions can be solved in the given time
2. Complete your preparation in stages according to the nature of the exam:
While preparing for some exams in which basic questions are asked in large numbers, prepare for them by completing all the chapters in the first stage.
A. Understand the basic definitions and formulas
B. Understand which formula to use in which situation through an example
C. Remember well what each notation in the formula means
D. Understand the process of how the unit and dimension of quantities are determined
E. Write down the formulas with three parameters in a separate diary
F. Memorize some standard solved questions.
Best wishes
Lovekush kumar
MSc Physics
IIT Delhi